Re: Ciekawa granica

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Article #109

#109

From: Robert Matuszewski
Date: Tue, 22 Mar 2005 20:42

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> > Witam grupowiczow.
> > Jak wiemy, granica przy x-->oo wyrazenia (1+a/x)^x jest rowna e^a.
> > Zadaniem jest obliczyc granice wyrazenia ((x+4)/(x-5))^(2x-1) przy
x -->oo.
> > Moze ktos ma jakis pomysl jak to rozpisac?
>
> (x+4)/(x-5) = (x-5+9)/(x-5) = (x-5)/(x-5) + 9/(x-5) = 1 + 9/(x-5)
>
>
> Dalej kombinuj juz sam :).

 Hehe no taki madry to ja sam bylem :)
WLasnie problemem jest to, co zrobic dalej? A moze jakos inaczej?
Pozdrawiam
RM

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From: "Robert Matuszewski" <nos...@e-mail.pl>
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Subject: Re: Ciekawa granica
Date: Tue, 22 Mar 2005 21:42:14 +0100
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