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Article #108Re: Ciekawa granica
From: Damian Sobota
Date: Tue, 22 Mar 2005 20:32
Date: Tue, 22 Mar 2005 20:32
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Robert Matuszewski napisaล(a): > Witam grupowiczow. > Jak wiemy, granica przy x-->oo wyrazenia (1+a/x)^x jest rowna e^a. > Zadaniem jest obliczyc granice wyrazenia ((x+4)/(x-5))^(2x-1) przy x -->oo. > Moze ktos ma jakis pomysl jak to rozpisac? (x+4)/(x-5) = (x-5+9)/(x-5) = (x-5)/(x-5) + 9/(x-5) = 1 + 9/(x-5) Dalej kombinuj juz sam :). -- Pozdrawiam, Damian Sobota.
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Path: mbox-mo1.pugleaf.net!g2news1.google.com!news4.google.com!news.glorb.com!nntp.idg.pl!wsisiz.edu.pl!newsfeed.tpinternet.pl!nemesis.news.tpi.pl!news.tpi.pl!not-for-mail From: Damian Sobota <dam.us...@wp.tezusun.pl> Newsgroups: alt.pl.matematyka Subject: Re: Ciekawa granica Date: Tue, 22 Mar 2005 21:32:34 +0100 Organization: tp.internet - http://www.tpi.pl/ Lines: 14 Message-ID: <d1pvm5$2oo$1@nemesis.news.tpi.pl> References: <d1pu96$2n3$1@wroclaw.wro.vectranet.pl> NNTP-Posting-Host: ase97.neoplus.adsl.tpnet.pl Mime-Version: 1.0 X-Trace: nemesis.news.tpi.pl 1111523845 2840 83.26.216.97 (22 Mar 2005 20:37:25 GMT) X-Complaints-To: use...@tpi.pl NNTP-Posting-Date: Tue, 22 Mar 2005 20:37:25 +0000 (UTC) User-Agent: Mozilla Thunderbird 1.0 (Windows/20041206) X-Accept-Language: pl, en-us, en In-Reply-To: <d1pu96$2n3$1@wroclaw.wro.vectranet.pl> Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit