Re: Zadanie z parametrem

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Article #398

#398

From: Coach
Date: Thu, 21 Apr 2005 18:15

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> PS.
> Mi wyszło, że m należy do zbioru: (-1;-1/sqrt(2)) u (-1/sqrt(2);
> 1/sqrt(2)) u (1/sqrt(2); 1)   ale mogę sie mylić
>
> Pozdrawiam
> Paweł
>

Czyli tez nie tak jak jest w odpowiedziach.... Ma ktoś inaczej?

Coach,

PS. 1/sqrt(2)=sqrt(2)/2 wiec nasze wyniki zbytnio sie nie roznia..

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From: "Coach" <mkolata@TEGONIEMA.poczta.onet.pl>
Newsgroups: alt.pl.matematyka
Subject: Re: Zadanie z parametrem
Date: Thu, 21 Apr 2005 20:15:13 +0200
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