Article View: pl.comp.programming
Article #216565Re: Ile zajmie komputerowi mnożenie liczb rzędu 2^128
From: osobliwy.nick
Date: Wed, 04 Dec 2019 11:43
Date: Wed, 04 Dec 2019 11:43
29 lines
2229 bytes
2229 bytes
> > Naprawdę będzie całkowita? Tak z ciekawości sprawdziłem dla 2^64 > > > > 2^64 -5= 18446744073709551611 * 2,5= 46116860184273879027,5 +2,5= 46116860184273879030 /2 > > =23058430092136939515 * 2,5 =57646075230342348787,5 +2,5 = 57646075230342348790 /2 = > > 28823037615171174395 *2,5= 72057594037927935993,75 + 2,5 ... > > Coś mi się źle wymnożyło :) Chyba tak. Kilka pierwszych wyrazów: 850705917302346158658436518579420528630 425352958651173079329218259289710264315 1063382396627932698323045648224275660790 531691198313966349161522824112137830395 1329227995784915872903807060280344575990 664613997892457936451903530140172287995 1661534994731144841129758825350430719990 830767497365572420564879412675215359995 2076918743413931051412198531688038399990 1038459371706965525706099265844019199995
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