Re: iteracja po tablicy kazdy z kazdym "ruby-way"

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Article #213

#213

From: Marcin Mielżyński
Date: Mon, 02 Oct 2006 20:27

38 lines
1556 bytes

Przemysław Kowalczyk wrote:
> Witam,
> 
> mam taki akademicki problem: jak zrobic jakas operacje na kazdej parze 
> elementow z jakiejs listy (tzn. kazdy z kazdym)? na razie robie to tak:
> 
> for i in 0..lst.size - 1
>     for j in i + 1..lst.size - 1
>         do_something(lst [i], lst [j])
>     end
> end
> 
> ale to wyglada dosc malo rubistycznie. jakies pomysly?
> 
> pzdr
>     szeryf

class Array

     def each_pair
         self.each_index do |i|
             (i+1).upto(self.size-1) do |j|
                 yield self[i],self[j]
             end
         end
     end

end

lst = *(1..10)

lst.each_pair do |a,b|
     puts "#{a} #{b}"
end



lopex

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From: Marcin Mielżyński <lopx@gazeta.pl>
Newsgroups: pl.comp.lang.ruby
Subject: Re: iteracja po tablicy kazdy z kazdym "ruby-way"
Date: Mon, 02 Oct 2006 22:27:02 +0200
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