Re: Interpolacja Liniowa

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#27544

From: Bart Ogryczak
Date: Mon, 28 Jun 2010 16:49

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On Jun 26, 8:41 pm, rav <rafalgulin...@gmail.com> wrote:
> Nie dziala kiedy x2-x1 == 0 (div by zero)
> dlatego dodalbym sprawdzenie roznicy tych wartosci do funkcji
>
> def getInterpolated(x0,y0, x1, y1):
>     if x1 - x0 == 0:
>         print 'x1 i x0 can\'t be equal'
>         return None
>     a = (y1 - y0) / (x1 - x0)
>     b = y0 - a * x0
>     def interpolate(x):
>         return a * x + b
>     return None

Pythonistycznie, to raczej będzie tak:

try:
    a = (y2 - y1) / (x2 - x1)
    b = ((-x1) * (y2 - y1) - (x2 - x1) * (-y1)) / (x2 - x1)
    def interpolate(x):
        return a * x + b
    return interpolate
except ZeroDivisionError:
    print 'x1 i x0 can\'t be equal'
    return None

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From: Bart Ogryczak <b.ogryczak@gmail.com>
Newsgroups: pl.comp.lang.python
Subject: Re: Interpolacja Liniowa
Date: Mon, 28 Jun 2010 09:49:06 -0700 (PDT)
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