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Article #2201

Re: Podobna zagadka

#2201
From: Bernard
Date: Sun, 11 Apr 2010 20:21
22 lines
1474 bytes
On 2010-04-09 23:00, Andrzej Grażyński wrote:
> Dane jest pole o adresie początku w ESI i długości w bajtach w ECX.
> Należy odwrócić kolejność BITÓW.

xlop:
     lodsb
	mov	ah, al
	and	ax, 0x55aa
	shr	al, 1
	aad	2
	mov	ah, al
	and	ax, 0x33cc
	shr	al, 2
	aad	4
	ror	al, 4
     xchg    al, [esi + ecx - 2]
	; i tu to samo, co powyżej - 9 instrukcji
     mov    [esi - 1], al
     sub    ecx, 2
     ja    xlop

razem 23 instrukcje na 1 obieg pętli
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From: Bernard <bernard@earth.net>
Newsgroups: pl.comp.lang.asm
Subject: Re: Podobna zagadka
Date: Sun, 11 Apr 2010 22:21:07 +0200
Organization: Aster Sp. z o.o.
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