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Article #9926

Re: Wspólne wyrazy dwóch ciągów

#9926
From: Mirek
Date: Mon, 31 Aug 2009 12:07
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On nie, 30 sie 2009 22:04:17 in article news:<d9d316c2-d36b-4148-ab0f-c183fde1fecd@y10g2000prg.googlegroups.com>
"Wlodzimierz Holsztynski (Wlod)" wrote:
>> ======================================
>> Dla  n >/ 0  mamy:
>>
>>     C(n+1)  =
>>
>>         min( ra * Sufit(C(n)/ra),  rb * Sufit(C(n)/rb) )
>>
> 
> To jest prawdą w dowolnym przypadku,
> a nie tylko w zredukowanym.

Moim skromnym zdaniem jest błąd, nie działa już dla n=0 ;)

Powinno być:

    min( ra * (1+floor(C(n)/ra)),  rb * (1+floor(C(n)/rb)) )
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Path: mbox-mo1.pugleaf.net!news-archive.icm.edu.pl!news.gazeta.pl!not-for-mail
From: Mirek <pisz_na.mirek@dionizos.zind.ikem.pwr.wroc.pl>
Newsgroups: alt.pl.matematyka
Subject: Re: Wspólne wyrazy
 dwóch ciągów
Date: Mon, 31 Aug 2009 12:07:22 +0000 (UTC)
Organization: WUT
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