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Article #198Re: zadanie na prawdopodobienstwo
From: Andrzej
Date: Thu, 07 Apr 2005 09:01
Date: Thu, 07 Apr 2005 09:01
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bierzesz sobie grupe B. mozesz wylosowac albo dwie kobity (zdX) albo kobite i faceta(zdY) . Jak wylosujesz dwie baby to musisz potem wylosowac z grupy A dwoch chlopa (zd X ciag dalszy), a jak wylosujesz kobite i faceta to musisz jeszcze raz znalezc kobite z facetem (zd Y ciag dalszy). czyli: P(X) = (1/3)* ((3 nad 2)/(4 nad 2)) P(Y)= (2/3 )* (3 / (4 nad 2)) czyli wynik = P(X) +P(Y) = 1/6 + 1/6 = 1/3 (chyba ;) pozdr Andrzej
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Path: mbox-mo1.pugleaf.net!news-archive.icm.edu.pl!newsfeed.gazeta.pl!news.onet.pl!newsfeed.tpinternet.pl!nemesis.news.tpi.pl!news.tpi.pl!not-for-mail From: "Andrzej" <ab@staszic.waw.wpl> Newsgroups: alt.pl.matematyka Subject: Re: zadanie na prawdopodobienstwo Date: Thu, 7 Apr 2005 11:01:00 +0200 Organization: tp.internet - http://www.tpi.pl/ Lines: 11 Message-ID: <d32sqf$obp$1@nemesis.news.tpi.pl> References: <d2sgn4$jnr$1@nemesis.news.tpi.pl> NNTP-Posting-Host: cpw103.neoplus.adsl.tpnet.pl X-Trace: nemesis.news.tpi.pl 1112864399 24953 83.31.228.103 (7 Apr 2005 08:59:59 GMT) X-Complaints-To: usenet@tpi.pl NNTP-Posting-Date: Thu, 7 Apr 2005 08:59:59 +0000 (UTC) X-Priority: 3 X-MSMail-Priority: Normal X-Newsreader: Microsoft Outlook Express 6.00.2600.0000 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2600.0000 MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 7bit